vincentchan Messages 609 Reaction score 0 Jan 11, 2005 #31 (1.6 x 10^ -19 C) (4.5 x 10^3 V) = 1/2 x 9.1 x 10^-31 x v^2 [tex]v=\sqrt{2(1.6*10^-19 * 4.5*10^3)/9.1*10^31}[/tex]
(1.6 x 10^ -19 C) (4.5 x 10^3 V) = 1/2 x 9.1 x 10^-31 x v^2 [tex]v=\sqrt{2(1.6*10^-19 * 4.5*10^3)/9.1*10^31}[/tex]
vincentchan Messages 609 Reaction score 0 Jan 11, 2005 #32 (1.6 x 10^-19 C) (4.5 x 10^3 V) = 1/2 x 9.1 x 10^-31 x v^2 [tex]v=\sqrt{2(1.6*10^{-19} * 4.5*10^3)/(9.1*10^{31})}[/tex] i think you get this part rite, check your arithmatic...
(1.6 x 10^-19 C) (4.5 x 10^3 V) = 1/2 x 9.1 x 10^-31 x v^2 [tex]v=\sqrt{2(1.6*10^{-19} * 4.5*10^3)/(9.1*10^{31})}[/tex] i think you get this part rite, check your arithmatic...