How Does Changing String Tension Affect Frequency in a Physics Problem?

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SUMMARY

The discussion centers on the relationship between string tension and frequency in a physics context, specifically involving two strings vibrating at 260 Hz. When one string is tightened, it produces 3 beats per second with the other string. The calculation using the beat frequency formula, Fbeat = F1 - F2, leads to confusion regarding the new frequency of the tightened string. The correct interpretation is that the tightened string's frequency must exceed 260 Hz, resulting in a new frequency of 263 Hz, as the tension increase directly correlates with frequency increase.

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  • Basic knowledge of string tension effects on vibration
  • Proficiency in using formulas related to frequency and tension
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Two strings are adjusted to vibrate at 260 Hz. One string is tightened then 3 beats per second is head when the string vibrate at the same time. What is the new frequency of the tightened string.
I am using Fbeat=F1-F2; so wouldn't the answer just be 263 Hz
 
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Well, can you explain why 263 Hz, and not 257 Hz?
 
The tension increased so the frequency must be greater than the F1. But when F2 is isolated the result would be 260-3 = 257hz
 

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