How Does Chirality Affect the Dirac Adjoint in Quantum Mechanics?

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SUMMARY

The discussion centers on the relationship between chirality and the Dirac adjoint in quantum mechanics, specifically how the chirality condition for a spinor \(\psi\) with plus chirality, defined by \(\gamma_5\psi=+\psi\), translates to the Dirac adjoint \(\bar{\psi}=\psi^\dagger i\gamma^0\). The calculation shows that the chirality condition can be rewritten as \(\bar{\psi}\gamma_5=-\bar{\psi}\). The conclusion drawn is that the expression \(\bar{\psi}\gamma_5\psi\) equals zero when \(\psi\) is chiral, confirming the consistency of the chirality condition.

PREREQUISITES
  • Understanding of Dirac spinors and adjoints
  • Familiarity with the properties of \(\gamma\) matrices in quantum mechanics
  • Knowledge of chirality and its implications in quantum field theory
  • Basic grasp of the mathematical framework of quantum mechanics
NEXT STEPS
  • Study the properties of \(\gamma\) matrices in detail, particularly in the context of quantum field theory
  • Explore the implications of chirality in the Standard Model of particle physics
  • Learn about the role of the Dirac equation in relativistic quantum mechanics
  • Investigate the concept of chiral components and their significance in quantum mechanics
USEFUL FOR

This discussion is beneficial for theoretical physicists, quantum mechanics students, and researchers focusing on particle physics and quantum field theory, particularly those interested in the implications of chirality in spinor fields.

synoe
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I have a question about chirality.
When a spinor \psi have plus chirality, namely
<br /> \gamma_5\psi=+\psi,<br />
how can I write this condition for the Dirac adjoint \bar{\psi}=\psi^\dagger i\gamma^0?

Let me choose the signature as \eta_{\mu\nu}=\mathrm{diag}(-,+,+,+) and define \gamma_5\equiv i\gamma^0\gamma^1\gamma^2\gamma^3. Taking the Dirac adjoint of the left hand side of the above equation,
<br /> (\gamma_5\psi)^\dagger i\gamma^0=\psi^\dagger\gamma^\dagger_5i\gamma^0\\<br /> =\psi^\dagger(-\gamma^0\gamma^0)\gamma_5i\gamma^0\\<br /> =\bar{\psi}\gamma^0\gamma^0\\<br /> =-\bar{\psi}\gamma_5,<br />
so the chirality condition seems to be rewritten as
<br /> \bar{\psi}\gamma_5=-\bar{\psi}.<br />

However, for example, considering a quantity \bar{\psi}\gamma_5\psi, this result is inconsistent. Where is wrong in the above calculation?
 
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It's not inconsistent, since ##\bar{\psi}\gamma_5 \psi =0## if ##\psi## is chiral. Essentially you have already proved it, but you can also verify it in terms of the chiral components.
 

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