The cosine of -π/2 equals 0 and the sine of -π/2 equals 1 due to the properties of trigonometric functions. Specifically, cosine is an even function, meaning cos(-θ) = cos(θ), while sine is an odd function, meaning sin(-θ) = -sin(θ). The angles in question are measured in radians, which is crucial for accurate calculations. Understanding these properties clarifies the results of these trigonometric evaluations.
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Notice that cosine is an even function and sine is an odd function.subopolois said:Homework Statement
can someone tell me how cos(-pi/2)=0?
and also how-sin(-pi/2)=1?Homework Equations
trigonometryThe Attempt at a Solution
ive tried using the two special triangles, but they haven't worked and i don't know what else to do