How Does Friction Influence Motion on an Incline?

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SUMMARY

The discussion focuses on the influence of friction on motion along an incline, specifically analyzing a block of mass m on a 20° slope with coefficients of static friction (µs = 0.74) and kinetic friction (µk = 0.52). The minimum mass m required to prevent slipping is calculated as 1.93 kg. For part B, the user incorrectly attempts to apply kinetic friction to determine the acceleration of the block when nudged, resulting in an erroneous mass of 2.4 kg instead of maintaining the established mass of 1.93 kg.

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The figure below shows a block of mass m resting on a 20° slope. The block has coefficients of friction µs = 0.74 and µk = 0.52 with the surface. It is connected via a massless string over a massless, frictionless pulley to a hanging block of mass 2.0 kg.


(a) What is the minimum mass m that will stick and not slip?
(b) If this minimum mass is nudged ever so slightly, it will start being pulled up the incline. What acceleration will it have?


fs= μs*N
F=M*A

I got part A correct.
m = 19.6 ÷ (9.8 * sin 20 + 0.74 * 9.8 * cos 20) = 1.93

but part B is not, I tried to use the same equation but change the static friction to kinetic

and got 2.4 as the mass

then F= MA
F = 2.4 (A)

I made a FBD and came up with

WME-fk - wsin\theta=a(M1+M2)

Is this on the right track?

thanks
 

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pumpernickel said:
but part B is not, I tried to use the same equation but change the static friction to kinetic

and got 2.4 as the mass
But the question states that the mass remains at the value 1.93
 

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