How Does Hitting a Cue Ball Above the Equator Affect Its Motion?

[bluejay1]

Homework Statement

A cue ball is hit 4.5 cm above the horizontal surface uk = 0.35 it is on.
The ball is 6 cm in diameter and has a mass of 250 g. It is hit
by a cue stick with an average force of
6000 N during a contact time of 20 usec.

(a) What is the ball’s speed after it is hit?

Homework Equations

F=Ma
x=x0+v0xt+1/2at^2

The Attempt at a Solution

I can't figure out the effect being hit above the equator has and how to incorporate it?
Thanks

 

[turin]

It sounds like they want you to take into account the torque on the cue ball due to the fact that it was hit off center. I guess you assume that the cue does not slip and that it hits parallel to the horizontal surface, but it doesn't actually say that, so I'm just guessing.