How Does Impulse Affect Momentum in Physics?

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Homework Help Overview

The discussion revolves around the application of the impulse-momentum theorem in a physics problem involving a 3.50-kg object with an initial velocity and a constant net force acting on it. The original poster attempts to calculate the final velocity of the object after a specified time using the impulse-momentum theorem.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the need to consider the direction of the force relative to the initial velocity and how this affects the application of the impulse-momentum theorem. The original poster questions where their reasoning may have gone wrong in their calculations.

Discussion Status

Some participants have provided guidance on the importance of including unit vectors in the calculations, emphasizing that momentum and impulse are vector quantities. The original poster acknowledges a mistake and indicates they will revise their approach based on the feedback received.

Contextual Notes

There is an emphasis on the correct representation of vector quantities in the calculations, and the discussion highlights the potential for misunderstanding when unit vectors are not included from the beginning.

bona0002
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Hey guys,

Alright, I feel like this is super easy, but for some reason, I'm not getting the right answer. Could you guys point out my flaw? There are (one can say) three coequal theories of motion for a single particle: Newton's second law, stating that the total force on an object causes its acceleration; the work–kinetic energy theorem, stating that the total work on an object causes its change in kinetic energy; and the impulse–momentum theorem, stating that the total impulse on an object causes its change in momentum. In this problem, you compare predictions of the three theories in one particular case. A 3.50-kg object has velocity 7.00j m/s. Then, a constant net force 8.0i N acts on the object for 4.50 s.
(a) Calculate the object's final velocity, using the impulse–momentum theorem.

Process:
The impulse-momentum theorem says that Δp = I.
With that said, we obviously need to find the v_f_, so I would speculate that the impulse-momentum theorem can be broken down to say mv_f_ - mv_i_ = I. Solving for v_f_, the expression becomes ((I + mv_i_)/m).
Now, I = F * Δt (because F is a constant force). Plugging in values, (8.o N) * (4.5s) = (36.0 N*s).
Therefore, plugging in the final value of impulse, v_f_ = ((36.0 N*s + (3.50 kg)(7.00 m/s))/(3.50 kg) = 17.3 m/s

So, with all that said, where am I going wrong?

Thanks!
 
Last edited:
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You haven't taken into account the fact that the force is not in the same direction as the initial velocity.
 
Taking that into account then, may I inquire how that changes the setup of my problem-solving process? Unfortunately, I'm not seeing it right now.
 
It doesn't change the general process. Momentum and impulse are vector quantities. So, the impulse-momentum theorem is ##\vec{I} = \Delta\vec{p}= m\vec{v}_f-m\vec{v}_i##. When you substitute for ##\vec{I}## and ##\vec{v}_i##, be sure to include the unit vectors ##\hat{i}## or ##\hat{j}##.
 
So, if I'm understanding this correctly, my substitution did yield the "correct" answer, it's just that the answer needs to be expressed in i and j hat notation?
 
No, your answer is incorrect because you didn't include the unit vectors during the calculation. It's not a matter of just putting in a unit vector at the end.
 
Ok, I'll reword it with the unit vectors in mind, and see what I come out with.
 
OK. Note, for example, the difference between 2 + 3 and 2##\hat{i}## + 3##\hat{j}##. The first summation yields 5, but the second summation gives something entirely different.
 
Ok, the answer worked out. That was a stupid mistake on my part. Thank you for the help!
 

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