How Does Molecular Kinetic Theory Explain the Behavior of Helium Gas Molecules?

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SUMMARY

The discussion focuses on calculating the total kinetic energy and root mean square speed of 1.0 mol of helium gas at a temperature of 27°C. The relevant formula used is \(\frac{m\bar{v^{2}}}{2}=\frac{3}{2}kT\), where \(k\) is the Boltzmann constant. Participants provided insights on how to derive the total kinetic energy and the implications of molecular kinetic theory on the behavior of helium gas molecules.

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khizman
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:confused: :redface: Hi got this question with which i need help

For 1.0 mol of helium at a temprature 27deg C calculate:-

i) the total kinetic energy of molecules,
ii) the root mean square speed of the molecules
 
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HINT:

[tex]\frac{m\bar{v^{2}}}{2}=\frac{3}{2}kT[/tex]

Daniel.
 

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