How Does Partial Fraction Decomposition Apply to Laplace Transforms?

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SUMMARY

The discussion focuses on the application of partial fraction decomposition to the Laplace transform of the function F(s) = 1/(s^2(s-2)). The correct decomposition is established as F(s) = 1/4 (-1/s - 2/s^2 + 1/(s-2)), contrary to the initial assumption of 1/s^2 - 1/(s-2). The method involves setting up the equation 1/(s^2(s-2)) = A/s + B/s^2 + C/(s-2), multiplying through by the denominator, and equating coefficients to solve for A, B, and C.

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reece
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Basically I don't know how F(s) can be split up to below.

F(s) = [tex]\frac{1}{s^{2}(s-2)}[/tex]

= [tex]\frac{1}{4}[/tex] ( - [tex]\frac{1}{s}[/tex] - 2 [tex]\frac{1}{s^{2}} + \frac{1}{s-2}[/tex] )

I thought it would be 1/s^2 - 1 / s-2

How does this work? Please explain.
thanks
 
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hey

try using partial fraction:

1/s^2(s-2)=A/s+B/s^2+C/(s-2)
then multiply both side of the identity by s^2(s-2)
then group the terms: s^2,s and constants(terms without s)
finally equate both sides of the identity. and then calculate A,B C
and then put in the term A/s+B/s^2+C/(s-2)
then you will find the expected form.

thanks

rezwan
 

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