How Does Particle P's Motion Change After 2 Seconds?

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After 2 seconds, particle P, initially located at (2,6) and moving with a velocity of (3i + j) ms-1, experiences a constant acceleration of (16i + 24j) ms-2. The calculations demonstrate that the particle's position after 2 seconds is (38, 66), confirming it is moving directly away from the origin O. The speed of the particle at that time is calculated to be approximately 30.0 ms-1.

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Can anyone help me with this question, please?

A particle P is initially at the point (2,6) in relation to an origin, O, and is moving with velocity (3i + j) ms-. It has constant acceleration (16i + 24j) ms-. Show that after 2 seconds it is moving directly away from O, and find its speed at that time.

I would greatly appreciate any help, also details of how to get the answer would be excellent!

Thanks.
 
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Welcome to the forums. Please note that, for homework questions, you are required to show some work before we can help you. Also, in the future, please post in the relevant homework/coursework forum.

So, how do you think you'll approach this question?
 
Sorry about not posting this in the correct place.

Well with this question, I was not sure about what I need to work out. Considering it is asking for me to firstly show its moving directly away from O, I thought that this may mean that moving directly away is the same as traveling due North (where i = 0).

The initial point (2,6) in component form would be (2i + 6j) with a magnitude of 6.32.

Though I am unsure as to what formula I need to apply to calculate the answer. (sorry for sounding so uncertain!)
 

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