- #1
robotopia
- 13
- 0
In this 1984 paper on circumstellar dust, the author says, speaking of the emissivity/absorption of dust grains at visual and infrared wavelengths:
My question is: where did the expression ##\lambda_p / 2\pi## come from, and what is the physical justification for it? I understand that small objects whose size is comparable to the wavelength of the incident light can't be resolved by that light, but what does that have to do with blackbody radiation and emissivity?
The dust shell model is consistent with the observed shape of the [IR] excess and the observed size of the ##60 \, \mu \text{m}## source, provided that ##(\varepsilon_\text{vis}/\varepsilon_\text{IR})## is near unity. Since ##\varepsilon_\text{vis}## for most material is near unity... it follows that ##\varepsilon_\text{IR}## also has to be near unity. This condition will normally be satisfied if the particle radius, ##a##, is comparable to or larger than ##\lambda_p / 2\pi##, where ##\lambda_p## is the wavelength of the peak emission.
My question is: where did the expression ##\lambda_p / 2\pi## come from, and what is the physical justification for it? I understand that small objects whose size is comparable to the wavelength of the incident light can't be resolved by that light, but what does that have to do with blackbody radiation and emissivity?