- #1

Javier Lopez

- 75

- 3

I do not understand the theory of moment of nuclei

I read here: http://www.sjsu.edu/faculty/watkins/nuclearmoment3.htm that the magnetic moment of Hydrogen is 2.79284734 magnetons = 2.79284734*9.274009994e-24 joules/tesla =2.59e-23 joules/tesla

So if I make to rotate a proton using 150 keV could I have a magnetic field at the proton surface accordingly following expresion?

$$\frac{150keV*1.6022*10^{-16}\frac{Joule}{keV}} {2.59*10{-23}\frac{Joules}{tesla}}=928 megateslas$$

Do I have to multiply with some constants?

Is the magnetic momento of a proton = 0?

I read here: http://www.sjsu.edu/faculty/watkins/nuclearmoment3.htm that the magnetic moment of Hydrogen is 2.79284734 magnetons = 2.79284734*9.274009994e-24 joules/tesla =2.59e-23 joules/tesla

So if I make to rotate a proton using 150 keV could I have a magnetic field at the proton surface accordingly following expresion?

$$\frac{150keV*1.6022*10^{-16}\frac{Joule}{keV}} {2.59*10{-23}\frac{Joules}{tesla}}=928 megateslas$$

Do I have to multiply with some constants?

Is the magnetic momento of a proton = 0?

Last edited: