How Does Rewinding a Coil Affect Its Self-Inductance and Energy Storage?

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SUMMARY

This discussion centers on the effects of rewinding a coil on its self-inductance and energy storage. When a coil is rewound to half the number of turns while maintaining the same diameter, its self-inductance is quartered, confirming that L = (1/4)*L. Additionally, when the current through an inductor is doubled, the energy stored increases by a factor of four, as described by the equation U = 0.5*L*I^2. The induced emf in a loop with a varying magnetic flux is calculated using the derivative of the flux function, yielding 31 V at t = 2 s.

PREREQUISITES
  • Understanding of self-inductance and its mathematical representation
  • Familiarity with the energy stored in inductors and the formula U = 0.5*L*I^2
  • Knowledge of magnetic flux and its relationship to induced emf
  • Ability to perform calculus operations, specifically differentiation
NEXT STEPS
  • Study the principles of electromagnetic induction and Faraday's Law
  • Explore the relationship between coil turns and self-inductance in detail
  • Learn about energy storage in inductors and its implications in circuit design
  • Investigate advanced topics in magnetic flux and its applications in electrical engineering
USEFUL FOR

Students in physics and electrical engineering, educators teaching electromagnetism, and professionals involved in circuit design and analysis will benefit from this discussion.

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Homework Statement



After you measure the self-inductance of a coil, you unwind it and then rewind half the length of wire into a coil with the same diameter but half the number of turns. How does this change the self-inductance?

a. It is the same.
b. It is doubled.
c. It is quadrupled.
d. It is halved.
e. It is quartered.

Homework Equations



See below.


The Attempt at a Solution



L = (N* magnetic flux)/i = (N*B*A*cos theta)/i = (n*l*A*B*cos theta)/(i), where N = n*l (l = wire length)

L2 = [(l/2)*A*(n/2)*B]/i = (1/4)*[(L*A*n*B)/i] = (1/4)*L??



Homework Statement


How much does the energy stored in an inductor change if the current through the inductor is doubled?

a. It remains the same.
b. It is doubled.
c. It is quadrupled.
d. It is halved.
e. It is quartered.




Homework Equations



See below.

The Attempt at a Solution



U = 0.5*L*I^2

U2 = 0.5*L*(2I)^2 = 4*0.5*L*I^2 = 4*U??


Homework Statement



The magnetic flux through a loop is made to vary according to the relation magnetic flux = 6t^2 + 7t + 1, where the units are SI. The emf induced in the loop when t = 2 s is

a. 38 V
b. 39 V
c. 40 V
d. 31 V
e. 19 V


Homework Equations



Emf_induced = -(d magnetic flux)/(dt)

The Attempt at a Solution



Taking the derivative, |emf| = 12t + 7, where t = 2 s

|Emf| = 12*(2s) + 7 = 31 V??

Thanks.
 
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You don't seem to be having any problems with this. They all look correct.
 

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