How does the equation-of-state depend on the Quintessence potential?

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Amanheis
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Quintessence fields are supposed to slowly roll down a potential V(\phi). Adding constants to the potential obviously does not change the equation of motion for this field, but it does change the pressure, energy density and equation-of-state. In particular, if I choose a sufficiently large positive consant, the equation of state
[tex]w = \frac{\dot \phi^2/2 - V(\phi)}{\dot \phi^2/2+V(\phi)}[/tex]
becomes eventually indistinguishable from -1.

Shouldn't physics stay invariant in this case?
 
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Amanheis said:
Quintessence fields are supposed to slowly roll down a potential V(\phi). Adding constants to the potential obviously does not change the equation of motion for this field, but it does change the pressure, energy density and equation-of-state. In particular, if I choose a sufficiently large positive consant, the equation of state
[tex]w = \frac{\dot \phi^2/2 - V(\phi)}{\dot \phi^2/2+V(\phi)}[/tex]
becomes eventually indistinguishable from -1.

Shouldn't physics stay invariant in this case?

yes,this potential is some quantily of energy density deimension and have absolute value to curve the space time.You can't redifine it by adding a constant. It is an extensive quantity right over there.