How does the equation-of-state depend on the Quintessence potential?

  • Thread starter Amanheis
  • Start date
  • #1
67
0

Main Question or Discussion Point

Quintessence fields are supposed to slowly roll down a potential V(\phi). Adding constants to the potential obviously does not change the equation of motion for this field, but it does change the pressure, energy density and equation-of-state. In particular, if I choose a sufficiently large positive consant, the equation of state
[tex]w = \frac{\dot \phi^2/2 - V(\phi)}{\dot \phi^2/2+V(\phi)}[/tex]
becomes eventually indistinguishable from -1.

Shouldn't physics stay invariant in this case?
 

Answers and Replies

  • #2
26
0
Quintessence fields are supposed to slowly roll down a potential V(\phi). Adding constants to the potential obviously does not change the equation of motion for this field, but it does change the pressure, energy density and equation-of-state. In particular, if I choose a sufficiently large positive consant, the equation of state
[tex]w = \frac{\dot \phi^2/2 - V(\phi)}{\dot \phi^2/2+V(\phi)}[/tex]
becomes eventually indistinguishable from -1.

Shouldn't physics stay invariant in this case?
yes,this potential is some quantily of energy density deimension and have absolute value to curve the space time.You can't redifine it by adding a constant. It is an extensive quantity right over there.
 

Related Threads for: How does the equation-of-state depend on the Quintessence potential?

Replies
9
Views
867
Replies
6
Views
959
  • Last Post
Replies
1
Views
2K
  • Last Post
Replies
1
Views
2K
  • Last Post
Replies
4
Views
3K
Replies
4
Views
767
Replies
7
Views
528
  • Last Post
Replies
8
Views
2K
Top