How Does the Lambda Zero Particle Decay Affect Kinetic Energy and Momentum?

[Fusilli_Jerry89]

Homework Statement

a subatomic particle called lambda zero decas spontaneously at rest into 2 other particles. Their masses are m(lambda zero) = 2183.3 me, m(1) = 273.2 me, m(2) = 1836.2 me, where me = 9.11E-31.
a) How muchkinetic energy in this process by loss of mass?

b) What is the momentum and kinetic energy of (1) and of (2)?

Homework Equations

K=0.5mv^2
p=mv

The Attempt at a Solution

a) How muchkinetic energy in this process by loss of mass?

All I did was use E=mc^2. I found the amount of mass missing, and multiplied it by the speed of light squared.

b) What is the momentum and kinetic energy of (1) and of (2)?

No idea how to do this?

I know that my answer for (a) equals the kinetic energies of the 2 particles added together. I'm lost from here...

 

[Astronuc]

m(1) = 273.2 me, $\pi^-$
m(2) = 1836.2 me, proton (p)

The lambda particle is at rest. The two particles, $\pi^-$ and p, travel in opposite directions. Conservation of momentum as well as energy.

http://hyperphysics.phy-astr.gsu.edu/hbase/particles/lambda.html