How Does the Work-Energy Theorem Determine the Initial Speed of a Sledgehammer?

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Homework Help Overview

The problem involves the application of the work-energy theorem to determine the initial speed of a sledgehammer after it strikes a pin, with a specific amount of work done on the pin. The subject area is primarily focused on mechanics, particularly the concepts of work and energy.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the application of the work-energy theorem and question the sign of the work done based on the direction of forces and displacement. There is an exploration of the implications of negative values in the context of the problem.

Discussion Status

The discussion is ongoing, with participants clarifying concepts related to the direction of forces and work done. Some guidance has been provided regarding the interpretation of the net force and its relationship to the displacement of the sledgehammer.

Contextual Notes

There is a mention of a specific answer being provided (14 m/s), but the participants are focused on understanding the reasoning behind the calculations rather than arriving at the answer itself. The original poster expresses confusion regarding the negative value encountered in their calculations.

aishax
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Homework Statement



490 J of work is done on a pin when a 5 kg sledgehammer strikes it (bringing the sledgehammer to rest). What is the initial speed of the sledge hammer.


Homework Equations



(Fnet)(d)= (0.5)(m)(velocity final^2 - velocity initial^2)


The Attempt at a Solution



490 = (0.5)(5)(0^2 - v inital^2)
980 = 5 (-v initial^2)
196 = - v initial^2


Problem is, v initial is now negative, and to get rid of the negative, I'd have to divide both sides by -1. But then it would be -196, and I would not be able to square root that. The answer is already given, and it is 14 m/s. It's just that one problem that has me stuck.

Help much appreciated :)
 
Last edited:
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The net force on the pin acts upward, and the displacemnt is downward, so the total work done of 490 J is positive or negative?
 
It would be negative.
But how is the net force on the pin acting upwards?
 
aishax said:
It would be negative.
But how is the net force on the pin acting upwards?

I think PhantomJay meant that the net force on the hammer is upwards, which is opposite to its displacement (hence the negative work done on the hammer and negative change in its kinetic energy).
 
Ahh, okay. That makes sense.
Thank you! :)
 
cepheid said:
I think PhantomJay meant that the net force on the hammer is upwards
Yes, thanks for the correction.
 

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