How Efficient Is a Solar Panel at Converting Sunlight to Electricity?

Click For Summary
SUMMARY

The efficiency of the solar panel measuring 58 cm x 53 cm is calculated to be 12.3%. This is determined by dividing the power output of the panel, 37.8 W, by the power delivered by sunlight, 307.4 W. The calculation confirms that the fraction of energy converted from sunlight to electricity is 0.123. The discussion clarifies that the efficiency cannot exceed 100%, reinforcing the correctness of the initial calculation.

PREREQUISITES
  • Understanding of basic electrical concepts (current, voltage, power)
  • Familiarity with solar panel specifications and measurements
  • Knowledge of efficiency calculations in energy conversion
  • Basic understanding of units of measurement (Watt, square meters)
NEXT STEPS
  • Research solar panel efficiency metrics and industry standards
  • Learn about different types of solar cells and their efficiencies
  • Explore methods to improve solar panel efficiency
  • Investigate the impact of environmental factors on solar energy conversion
USEFUL FOR

Students studying renewable energy, engineers working in solar technology, and anyone interested in understanding solar panel performance and efficiency calculations.

BillJ3986
Messages
6
Reaction score
0

Homework Statement


A solar panel (an assemblage of solar cells) measures 58 cm x 53 cm. When facing the sun, this panel generates 2.7A at 14V. Sunlight delivers an energy of 1.0 x 10^3 W/m^2 to an area facing it. What is the efficiency of this panel, that is, what fraction of the energy in sunlight is converted into electric energy?


Homework Equations


Am I doing this problem correctly


The Attempt at a Solution


The power delivered by the panel is P(delivered)= I x V= 2.7A x 14V= 37.8 W
For the power delivered by sunlight I multiplied 1.0 x 10^3 W/m^2 by the area of .58m x .53m:
so the area equals .307m^2.
1.0 x 10^3 W/m^2 x .307m^2= 307.4 W delivered by the sun.

So I needed to find the fraction of energy in sunlight that is converted into electric energy. I did that by dividing 37.8W/307.4. The fraction of energy converted is .123 or 12.3%.

Or is the answer 307.4/37.8= 8.13?

I'm not sure which is the right answer or if it I did it correctly please let me know.
 
Physics news on Phys.org
BillJ3986 said:
So I needed to find the fraction of energy in sunlight that is converted into electric energy. I did that by dividing 37.8W/307.4. The fraction of energy converted is .123 or 12.3%.
Looks good to me.

Or is the answer 307.4/37.8= 8.13?
No, you want the fraction of the energy in the sunlight that is converted to electrical energy. Your first answer was correct. (Efficiency could never be greater that 1 or 100%,)
 
Thank you.
 

Similar threads

Why Are Solar Panels 21-22% efficient? How can efficiency improved?
  • · Replies 3 ·
Replies
3
Views
1K
High School Using Interference Principles to Increase the Efficiency of Solar Panels
  • · Replies 0 ·
Replies
0
Views
1K
Undergrad Stirling engine against solar panels
  • · Replies 2 ·
Replies
2
Views
2K
How Much Heat Energy Can Be Harvested from Sunlight Per Square Meter in the UK?
  • · Replies 38 ·
2
Replies
38
Views
9K
Solar Panels and Solar Radiation Flux Density Help - Very Confused
  • · Replies 35 ·
2
Replies
35
Views
6K
How can I convert that Watt peak rating to Megawatt?
  • · Replies 9 ·
Replies
9
Views
6K
Calculating Power Diminishment of Nuclear Battery and Solar Panel over Time
  • · Replies 2 ·
Replies
2
Views
2K
Convert sunlight to electricity in a given area
  • · Replies 4 ·
Replies
4
Views
2K
How Long Will it Take to Heat Water Using a Solar Heater?
  • · Replies 2 ·
Replies
2
Views
2K
Undergrad Can solar panels be improved by combining them with a heat retaining material?
  • · Replies 7 ·
Replies
7
Views
2K