How far does a car travel before reaching a speed of 100 km/h?

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Homework Help Overview

The discussion revolves around a car's acceleration to a speed of 100 km/h and the distance it travels during this time. The original poster attempts to calculate the acceleration and displacement based on the time taken to reach the speed.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of acceleration and displacement, with some questioning the conversion from kilometers per hour to meters per second. There are also mentions of the assumption of constant acceleration and its implications on the results.

Discussion Status

Some participants have provided guidance on recalculating values and emphasized the importance of maintaining precision in calculations. There is acknowledgment of an error in the displacement formula, and the conversation reflects a mix of interpretations and approaches to the problem.

Contextual Notes

Participants note the need to clarify assumptions regarding constant acceleration, as this can significantly affect the outcomes of their calculations.

Stroodle
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A car is advertised as taking [tex]11.3\ s[/tex] to reach a speed of [tex]100\ kmh^{-1}[/tex]. About how far does it travel before reaching this speed?

Firstly I have tried to work out the acceleration: [tex]a=\frac{\frac{100000}{3600}}{11.3}\approx 0.2175\ ms^{-2}[/tex]

I've then used this to find the displacement: [tex]x=0.2175\times 11.3^2\approx 21.7\ m[/tex]

Am I doing something wrong? It seems like too short a displacement...

Thanks for your help
 
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Check your conversion from [tex]\tfrac{kilometers}{hour}[/tex] to [tex]\tfrac{meters}{second}[/tex].
Remember that for motion with constant acceleration, starting at rest, [tex]S=\tfrac{1}{2} a t^2[/tex]
Don't round your results so much. Keep your answer parametric until the very end. This is a skill you'll NEED once you get to the more complicated stuff.
You were off by a factor VERY different from [tex]10^n[/tex] in your calculation of the average acceleration.

Another thing I feel I should mention is that you need to state your assumption that the car accelerates with a constant acceleration, as that is not always the case, and your results will vary greatly should you consider such a case.
 
Last edited:
Awesome. Thanks for your help.
I'm now getting the answer as [tex]\approx 314\ m[/tex] with
[tex]a=\frac{2500}{1017}\ ms^{-2}[/tex]
Is that correct?
 
Last edited:
Stroodle said:
Awesome. Thanks for your help.
I'm now getting the answer as [tex]\approx 314\ m[/tex] with
[tex]a=\frac{2500}{1017}\ ms^{-2}[/tex]
Is that correct?

That is very close, you forgot the factor of [tex]\tfrac{1}{2}[/tex] in the displacement as a function of time formula.
 
Oh yeah. Oops.

Thanks again for your help. I'm sure these will become really easy after I do a few more of them.
 
Stroodle said:
Oh yeah. Oops.

Thanks again for your help. I'm sure these will become really easy after I do a few more of them.

Oh yeah, completely. By the time you get to the subject of work and energy, you'll be reciting these in your sleep. :)

And no problem, you're very welcome.
 

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