How Far is the Final Image from the Object in a Two-Lens System?

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SUMMARY

The discussion focuses on calculating the distance between an object and the final image in a two-lens optical system. The first lens has a focal length of 0.62 m, and the object is positioned 1.75 m to the left of this lens. The second lens, with a focal length of -2.7 m, is located 0.52 m to the right of the first lens. The calculations involve using the lens formula for both lenses, leading to the determination of the final image distance.

PREREQUISITES
  • Understanding of the lens formula: (1/x1) + (1/image) = (1/focal point 1)
  • Knowledge of the sign conventions for lens focal lengths
  • Familiarity with optical systems involving multiple lenses
  • Ability to perform algebraic manipulations to solve equations
NEXT STEPS
  • Review the derivation and application of the lens formula in optical physics
  • Study the impact of negative focal lengths on image formation
  • Explore examples of two-lens systems in optics
  • Practice solving problems involving multiple lenses and their configurations
USEFUL FOR

Students studying optics, physics educators, and anyone interested in understanding image formation in two-lens systems.

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Homework Statement



An object is 1.75 m to the left of a lens of focal length 0.62 m. A second lens of focal length -2.7 m is 0.52 m to the right of the first lens. Find the distance between the object and the final image formed by the second lens.

Homework Equations



(1/x1)+(1/image)= (1/focal point 1)

(1/x2 - image) + (1/x3)= (1/focal point 2)

The Attempt at a Solution



i use
x1=1.85
focal 1 = .62
solve for image in first equation

then use

x2=.52
focal 2 = -2.7
use the second equation and solve for x3
and get .526 m
i think I am following the steps right, but keep getting the wrong answer. any help would be great
thanks!
 
Physics news on Phys.org
In the problem xq1 is 1.75.
What is image distance?
 

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