How Far Will a 76 kg Person Fall with a Doubling Bungee Cord?

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    Bungee Mathematics
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Discussion Overview

The discussion revolves around determining how far a 76 kg person would fall when attached to a bungee cord that stretches to twice its natural length. The participants explore the relationship between mass, length, and the forces involved, while considering the lack of information about the cord's natural length.

Discussion Character

  • Exploratory
  • Technical explanation
  • Homework-related

Main Points Raised

  • One participant questions if there is a formula that relates length and mass for calculating the fall distance, given the absence of the natural length of the bungee cord.
  • Another participant suggests modeling the bungee cord as a spring and references the force exerted by the spring using the formula F = kΔx, noting that without the original length, Δx cannot be determined.
  • A different participant expresses confusion about the existence of a formula and seeks clarification, mentioning their teacher's belief that such a formula exists.
  • One participant proposes using a free body diagram to analyze the forces acting on the person, indicating that the net force at rest should equal zero, leading to an equation that could help find the spring constant k in terms of length and mass.
  • Another participant emphasizes the importance of knowing the elasticity constant if the natural length is unknown.

Areas of Agreement / Disagreement

Participants generally agree that the lack of information about the natural length of the bungee cord complicates the ability to derive a formula. However, there is no consensus on whether a definitive formula exists or how to proceed without that information.

Contextual Notes

The discussion highlights limitations due to missing assumptions about the bungee cord's natural length and elasticity constant, which affect the ability to derive a formula for the fall distance.

NicholasAllen
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Hi,

I was wondering whether there is a formula in terms of length and mass which would provide how far a person would fall is they were attached to a bungee cord rope which stretched to twice it's natural length when an object of 76 kilos was hung from it at REST from the free end?

I'm finding this difficult as we are not given a natural length... Oh also in this case I am neglecting the height of the person.

I am a Maths C student, so any physics explanations would not be much help as I'm hopeless at physics (whereas quite okay at maths c).

Thanks
 
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You're correct about not knowing the unstretched length. One could think of a bungee cord simply as a spring. In that case, the force exerted is:
[tex] F = k\Delta x[/tex]
Without the original length, you cannot find [tex]\Delta x[/tex] and therefore the instantaneous force exerted on the mass by the cord.
 
So does that mean there is no formula?
Because my maths C teacher is convinced there is, and i need it as a preliminary sort of thing to begin an assignment - maybe it is a formula in terms of x, l and m ?
 
I mean that's the formula for the resistance felt by the person. You could draw a free body diagram; the net force being mass times acceleration. The forces in each direction are mass and the resistance force from the bungee. However, saying that the cord will stretch twice it's length, but not specifying that length will not allow a person to get the change in length of the cord.
 
This can be done by assuming the rope behaves as a spring as minger described.

-Draw free body diagram of the person at rest hanging from the end of the rope using the known condition (76 kg mass, delta x = l)
-> At rest means no acceleration, therefore the vector sum of all forces adds up to zero. This leads to an equation.
-> Solve for spring constant k in terms of l and m

Since this is homework I'm not going to give you the rest of the solution, but hopefully now that you know the spring constant, and what minger described, you can come up with something on your own for the variable mass case...
 
If you don't know the natural length, you must know the elasticity constant.
 

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