How far will a car coast up a slope before rolling back down?

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Homework Help Overview

The problem involves a car coasting up a slope after running out of gas, specifically examining how far it will travel before rolling back down. The subject area includes concepts from kinematics and energy conservation.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply energy conservation principles to determine the height the car reaches. Some participants suggest the need for trigonometric functions to find the actual distance traveled along the slope.

Discussion Status

Participants are exploring the relationship between height and distance along the slope, with some guidance offered regarding the use of trigonometry to find the distance up the hill. There is acknowledgment of the need to clarify the distinction between height and distance traveled.

Contextual Notes

There is a mention of potential confusion regarding the application of trigonometric functions and the distinction between height and the distance along the slope. The original poster expresses uncertainty about the correctness of their initial calculations.

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A car traveling at 16.0 m/s runs out of gas while traveling up a 21.0 degree slope.

How far up the hill will it coast before starting to roll back down?

I tried

1/2mv^2=mgh
1/2(16)^2=9.8h
13.06=h

can anyone confirm if this is correct or not. I;m not sure if I have to use trig to solve this or not.

help please.
 
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looks good. the question is asking for the distance up the hill not just simply the height difference, so you'll have to use trig to find that.
 
si it would be sin(21)=13.06/x

x being the hyp/answer?
 
yea that was the answer
 

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