1. The problem statement, all variables and given/known data John and Fred are racing. Fred, being faster, gives john a 20 s head start. John runs at 12 km/hr (10/3 m per second) and Fred at 16 km/hr (40/9 m per second) How long after John starts will Fred catch him? How far from the start do the two meet? 2. Relevant equations d = 1/2 (Vf + Vi) t 3. The attempt at a solution my list of givens: -Vi (10/3 for John, and 40/9 for Fred) -Vf = 0 (for both) d for Fred = d for John (displacements are equal) what I do not know: -time taken -displacement I know that I could use kinematic equations, but I don't really know which ones to use (except for the one I wrote here) so I tried to take a very basic algebra approach to it. I figured out how far John traveled in the 20 second head start that he got (200/3 m) and then I set it up in a "solve for x" style. so: 10/3 x +200/3 = 40/9 x, and then I got that x (time) equals 60 seconds, and then added 20 seconds (john's head start) to get that the time at which their displacements are equal is 80 s. I then plugged it back into the original equation and figured out that the distance traveled was 266.7 m until Fred caught John. So first off, are those values correct? and secondly, how do I do that exact problem, but instead using kinematic equations?