- #1

scytherz

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## Homework Statement

A 1967 Corvette has a weight of 3020 lbs. The 427 cu-in engine was rated at 435 hp at 5400 rpm. a) If the engine used all 435 hp at 100% efficiency during acceleration, what speed would the car attain after 6 seconds? b) What is the average acceleration? (in “g”s).

## Homework Equations

P= W/t

ke =.5mv^2

1 hp = 746 W = 550 ft lb/s

## The Attempt at a Solution

P= (fd)/t , since f = Mg, P= MgV,

P= 435 hp = 324 510 kg m^2/s^2 (W) = Mgv = 1372.73 kg(9.8m/s^2)(v)

i got v= 24/6 = 4.02m/s.. converting to mph, ans is 8.99 mph... which is wrong.. the ans.. is

**120mph...**

I also tried using P = W/t , by finding the work, w= pt, w= 1 947 060 Nm, then substitute on k= mv^2, but still wrong...

I don't where did i go wrong, but do i still to put into consideration the 427 cu in engine and the efficiency rate or just ignore it??