How Fast Does a Book Fall from 4.20 Meters?

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Homework Help Overview

The problem involves determining the speed of a physics book just before it impacts the ground after being dropped from a height of 4.20 meters, with the assumption that air resistance is negligible. The discussion centers around concepts of energy conservation and kinematics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to relate potential energy to kinetic energy but expresses confusion about the role of mass in the calculations. Some participants suggest using conservation of energy principles to simplify the problem, while others propose using kinematic equations to find the final velocity.

Discussion Status

Participants are exploring different methods to approach the problem, with some expressing satisfaction in the equivalence of the results obtained through various equations. There is an ongoing exchange of ideas regarding the application of energy conservation and kinematic equations.

Contextual Notes

The original poster notes a lack of information regarding mass, which they believe complicates their ability to solve the problem. The discussion reflects an understanding of the principles involved but highlights uncertainties in applying them effectively.

kissafilipino
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A physics book of unknown mass is dropped 4.20 m. What speed does the book have just before it hits the ground? Unless otherwise directed, assume that air resistance is negligible.

Height: 4.20
Acceleration: 9.81
Mass: ?
Velocity: ?

The answer box is for velocity: ___ m/s

Homework Equations


1)Kinetic Energy: 1/2*m*v^2
2)Kinetic Energy: (p^2)/2*m

3)Potential Grav. Energy: m*g*(delta or change in)h


The Attempt at a Solution



I thought the whole point was to look at how the Potential energy becomes kinetic energy, and so I went about it by using the Potential energy formula. m(9.81)(4.40) = 43.164 however I don't know if I that gives me mass or anything, I am stumped because I think I do not have enough information to answer this question. Plus going about it by using another formula but that does not seem to be working either, such as the Force = mass times acceleration, again I do not know mass, or the power = force times velocity, again I need to find force, which I do not know. Please help me!
 
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U= potential energy
K= kinetic energy
Conservation of energy => Kf + Uf = Ki + Ui
What is the initial Kinetic Energy? (it has v=0)
What is the final potential energy? (it has h=0)
this should simplify this equation so that we have our kinetic = potential
And when you solve..the mass should cancel out.
 
I'm satisfied with MillerGenuine's method, But I have another method. In the problem you know initial velocity which is zero, total displacement i.e. height, acceleration.
So you can think of
vf^2=vi^2+2as.
 
THANKYOU, both your equations and formulas got the same answer (of course) but now I understand how it is possible and two ways of solving this type of question.
 

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