How Fast Does the Block Move After the Bullet Embeds?

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SUMMARY

The discussion centers on a physics problem involving a rifle bullet of mass 7.2 grams embedding into a block of mass 0.819 kg on a frictionless surface, compressing a spring by 17 centimeters. The spring constant is derived from the force of 0.68 Newtons required to compress the spring 0.31 cm. The correct approach to find the block's velocity after impact involves using conservation of momentum and the spring's potential energy, leading to the conclusion that the spring constant (k) is essential for solving the problem accurately.

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Homework Statement


A rifle bullet of mass 7.2 grams strikes and embeds itself in a block with mass 0.819 kg that rests on a frictionless horizontal surface and is attached to a coil spring. The impact compresses the spring 17 centimeters. Calibration of the spring shows that a force of 0.68 Newtons is required to compress the spring 0.31 cm. Find the magnitude of the block’s velocity just after impact. Give your answer in m/s to the first decimal place.


Homework Equations





The Attempt at a Solution


I have looked at at least 4 other posts on this forum about this question, but I still cannot quite get it.

m1v1 = (m1+m2)v2

Using some dimensional analysis, I get that force is equal to some 37 N. Multiply this with the 17 cm, and you get the work done on the spring. This is equal to .5 * m * v1^2. Solve this for V1, plug back into the momentum equation to get V2. Is this not correct because my answer differs from the solution.
 
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Ok, so I finally found the solution, and it's something pretty stupid that I never thought of. k the spring constant is given, then everything else is simple.
 

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