Collisions - bullet shot in in block

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SUMMARY

The discussion centers on a physics problem involving three blocks of mass 3.00 kg, 2.00 kg, and 1.00 kg on a frictionless surface, with a 25 g bullet impacting the first block and embedding into the second. The final velocity of the third block is given as 5.00 m/s, prompting calculations for the velocity of block 2 before the collision, the bullet's velocity prior to embedding, the speed of block 1 after the bullet passes through, and the percentage of initial bullet energy lost. The user initially applied the formula (2m1/m2+m2)* v1 but expressed uncertainty about the results, indicating a need for clarification on the calculations.

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Ajmathusek
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Three blocks (1,2,3) of mass 3.00 kg, 2.00 kg, 1.00 kg sit
linearly 10.0 cm apart from each other on a frictionless surface.
A 25 g bullet is shot at the first block, it travels through the first
block, and embeds itself into the second block (without falling over) which then collides into the
third block.
a. Assuming the final collision is elastic, and the third block has a final velocity of 5.00 m/s, what is
the velocity of block 2 just before it collides into block 3?
b. What is the velocity of the bullet before it embeds itself into block 2?
c. Assuming the bullet slowed down by only 10% while it traveled through block 1, what was the
speed of block 1 after the bullet traveled through it?
d. What percent of the initial energy of the bullet was lost?

I tried using the formula (2m1/m2+m2)* v1 for all the question in the problem. But the numbers don't sound right to me.
 
Last edited:
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Ajmathusek said:
I tried using the formula (2m1/m2+m2)* v1 for all the question in the problem. But the numbers don't sound right to me.
Please show your calculations and numbers then. Otherwise we have no way to tell what went wrong. Your formula looks a bit odd, but that could be a typo.

Note that some collisions are not elastic.
 

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