How Fast Does the Ladder Slide Down the Wall?

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SUMMARY

The discussion focuses on solving two related problems using differentiation and the Pythagorean Theorem. The first problem involves a 25-foot ladder sliding down a wall, where the base is pulled away at 2 feet per second, and the goal is to find the rate at which the top of the ladder descends when the base is 15 feet from the wall. The second problem addresses a rocket launched vertically, tracked by a radar station 12 kilometers away, with the rocket's distance increasing at 2500 km/hr when it is 20 km away from the station. Both problems require the application of differentiation and the Pythagorean Theorem to derive the necessary rates of change.

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Use differentiation to solve the following

A ladder 25 feet long is leaning against the wall of a house. The base of the ladder is pulled away from the wall at rate of 2 feet per second. How fast is the top moving down the wall when the base of ladder is 15 feet from the wall.

What's the equation?

Thanks
 
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Use the Pythagorean Theorem.

x^2 + y^2 = z^2

Diffentiate:

x\frac{dx}{dt} + y \frac{dy}{dt} = z\frac{dz}{dt}

Solve for the desired variable, dy/dt in this case

\frac{dy}{dt} = \frac{z\frac{dz}{dt} - x\frac{dx}{dt}}{y}

Plug in values you know, using x^2 + y^2 = z^2 to determine distances you don't.

cookiemonster
 
how about this one

Using Differentiation solve

a rocket is launched vertically and is tracked by a radar station located on the ground 12 kilometers from the launch site. When the rocket is 20 km away from the radar station, its distance from the station is increasing at the rate of 2500 km/hr. What is the vertical speed of the rocket at this instant?

What is the equation?

Thanks
 
Same approach as the previous problem. Now you know x, y and can find z from Pyth. What is important is understanding what dx/dt and dy/dt are equal to.

Typically, we can help you only if you show us what you have tried and where you are stuck. We are not here to provide solutions to your homework.
 

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