How Fast Must Bruce Throw the Bagels for Henrietta to Catch Them?

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SUMMARY

To determine the initial speed at which Bruce must throw the bagels for Henrietta to catch them, one must analyze the motion in both horizontal and vertical directions. Bruce throws the bagels horizontally from a height of 48.5 meters, while Henrietta jogs at a speed of 3.90 m/s. The calculations involve using the equations of motion, specifically \( h = 0.5gT^2 \) to find the time of flight and the horizontal distance covered during that time. The solution requires understanding relative velocity and projectile motion principles.

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Homework Statement


Henrietta is going off to her physics class, jogging down the sidewalk at a speed of 3.90 m/s. Her husband Bruce suddenly realized that she left in such a hurry that she forgot her lunch of bagels, so he runs to the window of their apartment, which is a height of 48.5 m above the street level and directly above the sidewalk (SO I AM GUESSING IT IS 48.5 METERS ABOVE THE SIDEWALK, REALLY BAD WORDING) to throw them to her. Bruce throws them horizontally at a time 9.00 s after Henrietta has passed below the window and she catches them on the run. You can ignore air resistance.

a. With what initial speed must Bruce throw the bagels so Henrietta can catch them before they hit the ground?

b. Where is henrietta when she catch the bagels?

Homework Equations


y= -48.5 m
Vo= 3.90 m/s
and she took 9 seconds to walk down below the window.


The Attempt at a Solution



I made a x and y direction table but am totally lost. I was thinking that you would need to use the relative velocity equations but I don't know whether the bagels would be relative to the ground or to henrietta. So, if you could please guide me in a direction, that would be great. THANKS for any help.
 
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velocity of lunch*T = v of her wife * 9 + v of her wife * T

and using h = 0.5gT^2

find T
 
thanks for guiding me. I appreciate it a lot.
 

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