How fast should a space station rotate to simulate Earth's gravity?

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Homework Help Overview

The discussion revolves around determining the rotational speed required for a space station, shaped as a hollow ring with a diameter of 450 m, to simulate Earth's gravity for astronauts at its outer edge. The problem involves concepts of centripetal force and the relationship between angular velocity and gravitational force.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between centripetal force and gravitational force, questioning how to equate the normal force experienced by an astronaut to their weight. They discuss the formulas for centripetal force and angular velocity, and how to convert angular frequency to revolutions per minute.

Discussion Status

The discussion has progressed with participants sharing insights on relevant formulas and conversions. Some have successfully derived angular velocity and are working on converting it to the desired units. There is an ongoing exploration of the relationships between the forces involved.

Contextual Notes

Participants are navigating through the problem with a focus on understanding the physics concepts involved, including the implications of mass cancellation in the equations and the necessary unit conversions for angular frequency.

orange03
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A space station is in the shape of a hollow ring, 450 m in diameter. At how many revolutions per minute should it rotate in order to simulate Earth's gravity-that is, so that the normal force on an astronaut at the outer edge would be the astronaut's weight on Earth?

All I got so far was finding the circumference=pid=1413 meters. I'm stuck, I don't know what to do next. Help please!
 
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So the space station is rotating, thus there is a centripetal force. Do you know what that is?
 
Yeah, it's the force that is the same direction as acceleration, towards the center.
 
orange03 said:
Yeah, it's the force that is the same direction as acceleration, towards the center.

Right then. So you want the space station to produce a force which is equal to the weight of the astronaut. Can you make a relation between this force and the weight?
 
would it just be N=mg?
 
orange03 said:
would it just be N=mg?

Yes the normal force on the astronaut is =mg. BUT you want the space station to spin to produce a force which equals mg. Do you know any formulas for centripetal force?
 
F=mrw^2?
 
orange03 said:
F=mrw^2?

yes, so you want mw2r=mg

can you find w and then convert that to RPM?
 
okay i got w=.20 but I don't know how to convert that to RPM. Wouldn't the units on w by 1/s^2? Is there a formula or conversion factor to get it to RPM?
 
  • #10
Note that in the equation mw2r=mg, the mass is the same.

So dividing by mass, it become w2r=g.

g had unit of m/s2, and since r had units of m (meters, length), then w2 must give units of 1/s2.

w is angular frequency which is expressed in 1/s, and it's actually radians/s. Now since 1 revolution passes through 2pi radians, then 1 rps (revolution per second) = 2pi rad/s.

The frequency in revolutions per unit time = f = w/2pi = 1/T, where T = the period.

Conversely, w = 2pi f
 
  • #11
orange03 said:
okay i got w=.20 but I don't know how to convert that to RPM. Wouldn't the units on w by 1/s^2? Is there a formula or conversion factor to get it to RPM?

Right then w=0.2 rad/s and you want it in revolutions per minute.

In 1 revolution, the station rotates 2pi radians.
So 1 rad = 1 rev/2pi.

60 seconds = 1min

so

[tex]1 \frac{radian}{seconds} = \frac{60}{2 \pi} revolutions/min[/tex]
 
  • #12
Okay, I got it now. Thank you!
 

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