How High Does a Coin Tossed Straight Up Reach?

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Homework Help Overview

The problem involves analyzing the motion of a coin tossed straight up, specifically determining its maximum height given the time of flight and initial height above the ground.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Some participants discuss using kinematic equations to relate initial velocity, time, and maximum height. Others express uncertainty about the problem and seek detailed explanations.

Discussion Status

Participants are exploring different kinematic equations to approach the problem. Some have suggested specific formulas, while others are still trying to understand the concepts involved. There is no explicit consensus on the best method yet.

Contextual Notes

The original poster expresses a lack of understanding and requests a detailed explanation, indicating they may be struggling with the underlying physics concepts. The problem is framed within the constraints of a homework assignment.

student54321
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Homework Statement


A coin tossed straight up into the air takes
2.75 s to go up and down from its initial
release point 1.30 m above the ground.

What is its maximum height?


Homework Equations




The Attempt at a Solution





I seriously have no clue how to do this problem. I really need a detailed explanation with steps. I'm sorry if this doesn't abide by your question standards, but I really mean I have 0 idea how to solve this problem, and I really need some help.


Thanks.
 
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can anyone help?
 
its 1.30 + V0^2/2g

since V^2=V0^2 + 2g(ay) where the max height is when V=0
 
where V0=g(2.75/2) since V= V0 + gt where V=0m/s since you are accounting for the time it takes and the velocity at the point it goes its max height.
 

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