1. The problem statement, all variables and given/known data (A)A rubber band slingshot shoots a 25g stone What is the intial speed of a stone if the rubber band is drawn back 0.15m with a force of 27N? (B) How high will the stone rise if it is shot straight upward? m=0.025kg x=0.15m F=27N 2. Relevant equations Ep=1/2Fx For this question in order to find velocity i believe one has to assume Ep=Ek Ek=1/2mv2 v2=2W/m d=W/F 3. The attempt at a solution Ep=1/2Fx Ep=1/2(27N)(0.15m) Ep=2.025J Elastic potential energy is converted to kinetic energy when it is shot from the slingshot therefore: Ep->Ek 2.025J=1/2mv2 v2=(2.025 J)(2)/(0.025kg) v=12.73m/s I believe that this would be the initial speed of the stone after being shot however i am having difficulties determining how high the stone would rise if it is shot straight upwards as asked in part (B) The formula that i think would work is d=W/F however im not sure what W and F are especially considering gravity. How do i determine these factors?? Thank-you for taking a look!