How Is Acceleration Calculated When a Car Changes Direction But Not Speed?

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SUMMARY

The average acceleration of a car traveling at a constant speed of 20 m/s while changing direction from northwest to northeast over a period of 10 seconds is not zero, despite the constant speed. The calculation involves determining the change in velocity, which is a vector quantity, and applying the formula for acceleration: acceleration = change in velocity / change in time. The correct approach requires sketching a motion diagram to visualize the change in direction and accurately compute the average acceleration.

PREREQUISITES
  • Understanding of vector quantities in physics
  • Familiarity with the concept of average acceleration
  • Knowledge of motion diagrams
  • Basic proficiency in trigonometry for vector resolution
NEXT STEPS
  • Study vector addition and subtraction in physics
  • Learn how to sketch and interpret motion diagrams
  • Explore the concept of centripetal acceleration in circular motion
  • Review examples of average acceleration calculations in physics problems
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Students studying physics, particularly those focusing on kinematics and vector analysis, as well as educators seeking to explain concepts of acceleration and motion direction changes.

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Homework Statement


A car traveling at a constant speed of 20 m/s that is initially traveling due northwest rounds a corner so that after 10 s, the car is traveling due northeast. What are the magnitude and direction of the car's average acceleration during this interval of time? Be sure to sketch a motion diagram for process as well.


Homework Equations



acceleration = change in velocity / change in time

The Attempt at a Solution



Since the car is traveling at a constant speed, I would assume that the acceleration is zero. However, this does not seem right by the content of the question. Could someone please help me get started?
 
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possum30540 said:

Homework Statement


A car traveling at a constant speed of 20 m/s that is initially traveling due northwest rounds a corner so that after 10 s, the car is traveling due northeast. What are the magnitude and direction of the car's average acceleration during this interval of time? Be sure to sketch a motion diagram for process as well.

Homework Equations



acceleration = change in velocity / change in time

The Attempt at a Solution



Since the car is traveling at a constant speed, I would assume that the acceleration is zero. However, this does not seem right by the content of the question. Could someone please help me get started?

Velocity and acceleration are Vectors.

So ... Change in Velocity / change in time =
 

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