1. The problem statement, all variables and given/known data An object starts from rest and uniformly acquires a velocity of 20.0 m/s in 5.0 minutes. For the next 10. minutes the object moves with a constant speed. After 10. minutes moving at 20. m/s the object then again accelerates and reaches a speed of 15 m/s in the opposite direction in 3.0 minutes time. Calculate the time at which the object changes direction 2. Relevant equations y=mx+b v=d/t 3. The attempt at a solution made velocity time graph. tried to find the equation y=mx + b. already knew that slope + -.19 unknown what b is and i found that velocity = 0 when time is at 1005.275 seconds however it said this was wrong. I am very confused and jumbled. Unsure how to find displacement since it crosses the x axis and moves into negative.