How Is Energy Calculated for a Temperature Increase in Neon Gas?

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SUMMARY

The discussion focuses on calculating the energy absorbed by 180 g of neon gas to achieve a temperature increase of 12 K using the formula Q = m.c.dT. The mass (m) is specified as 180 g, while the specific heat capacity (c) must be referenced from a table for neon gas. Additionally, the conversation touches on constructing a PV diagram for isobaric and isothermal processes, as well as determining the highest possible exhaust temperature for an engine with 27% efficiency operating at 420°C.

PREREQUISITES
  • Understanding of thermodynamic principles, specifically the first law of thermodynamics.
  • Familiarity with the specific heat capacity of gases, particularly neon.
  • Knowledge of PV diagrams and the significance of isobaric and isothermal processes.
  • Basic concepts of engine efficiency and thermodynamic cycles.
NEXT STEPS
  • Research the specific heat capacity of neon gas at constant volume.
  • Learn how to construct and interpret PV diagrams for various thermodynamic processes.
  • Study the calculations involved in determining exhaust temperatures based on engine efficiency.
  • Explore the implications of cyclic processes in thermodynamics and their applications in real-world engines.
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Students and professionals in thermodynamics, mechanical engineers, and anyone interested in understanding energy calculations related to gas behavior and engine efficiency.

truckerron1
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i have 3 questions that i need help with

Consider 180 g of neon gas. How much energy would it have to absorb to experience a temperature increase of 12 K?

Construct a PV diagram for each of the following. (a) A gas begins with a volume of 14 L under pressure of 3 atm. The gas first undergoes an isobaric compression to a volume of 6 L. Next, the gas experiences an isothermal expansion back to a volume of 14 L. (b). A gas undergoes a cyclic process consisting of two isochoric processes and two isobaric processes.

A particular engine having efficiency 27% operates at temperature 420C. What is its highest possible exhaust temperature?

thanks ron
 
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I will just help you with the first question.
Consider this formula:

Q = m.c.dT

m= 180 g
c= ? -> you have to check on a table
dT = 12 K

Now, it's up to you. :biggrin:
 

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