How Is Jordan Normal Form Useful for Physicists?

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Homework Help Overview

The discussion revolves around the Jordan normal form of matrices, particularly its relevance and applications in physics. Participants explore the concept of "almost" diagonalizing matrices that are not diagonalizable and seek to understand its significance in various physical problems.

Discussion Character

  • Conceptual clarification, Exploratory

Approaches and Questions Raised

  • Participants discuss the ease of reading eigenvalues and eigenvectors from the Jordan form and question the importance of eigenvalues for non-diagonalizable matrices. There is also mention of using Jordan normal form to compute matrix exponentials in the context of differential equations.

Discussion Status

The conversation is ongoing, with participants sharing insights about the utility of Jordan normal form in reading eigenvalues and eigenvectors, as well as its application in solving linear systems. There is no explicit consensus yet, as questions about the importance of eigenvalues remain open for further exploration.

Contextual Notes

Participants note that the discussion is not a homework question but is related to course content, indicating a focus on understanding theoretical concepts rather than solving specific problems.

fluidistic
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Hi guys,
This isn't a homework question but it's course related. In my mathematical methods in Physics course we were introduced the Jordan normal form of a matrix.
I didn't grasp all. What I understood is that when a matrix isn't diagonalizable, it's still possible (only sometimes; depending on the given matrix), to "almost" diagonalize it.
I'd like to know what is the point of doing so, especially how can it be used for physicists and in what kind of problems such matrices can appear.
Thanks a lot!
 
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The main reason it helps is because you can read the eigenvectors and eigenvalues off very easily. The eigenvalues are along the diagonal. Each Jordan block yields only one eigenvector which is the column vector of the form (1, 0, 0...)^{T} so you can organize your matrix into many Jordan Blocks and you have your eigenvectors too.

Maybe there are more uses but this is what strikes me as most significant.
 
McLaren Rulez said:
The main reason it helps is because you can read the eigenvectors and eigenvalues off very easily. The eigenvalues are along the diagonal. Each Jordan block yields only one eigenvector which is the column vector of the form (1, 0, 0...)^{T} so you can organize your matrix into many Jordan Blocks and you have your eigenvectors too.

Maybe there are more uses but this is what strikes me as most significant.

Thanks. I knew this but why would knowing eigenvalues be important if the matrix isn't even diagonalizable?
 
fluidistic said:
Hi guys,
This isn't a homework question but it's course related. In my mathematical methods in Physics course we were introduced the Jordan normal form of a matrix.
I didn't grasp all. What I understood is that when a matrix isn't diagonalizable, it's still possible (only sometimes; depending on the given matrix), to "almost" diagonalize it.
I'd like to know what is the point of doing so, especially how can it be used for physicists and in what kind of problems such matrices can appear.
Thanks a lot!

You need it in computing functions of the matrix. For example, one way to solve a linear system of constant-coefficient DEs of the form dX/dt = A*x is to write X(t) = X_0*exp(A*t), so you need the exponential of a matrix. Knowing the Jordan normal form allows you to write down the matrix exponential explicitly.

RGV
 

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