How is observer defined in context to quantum physics?does it have

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In quantum physics, an observer does not need to be conscious; any interaction that can yield information about a quantum state is considered an observation. This includes applying mathematical operators, such as measuring a particle's position, which can collapse the wave function and affect the outcome of experiments like the double-slit experiment. The discussion highlights that the presence of potential measurement tools influences whether an interference pattern appears, regardless of actual observation. If one observer measures which slit a particle passes through, the interference pattern is lost, demonstrating the principle that knowledge gained from measurements collapses quantum states. The conversation emphasizes the importance of understanding these concepts through foundational texts in quantum mechanics.
  • #31


I like Serena said:
Yep! :)

Any light source that makes it observable through which slit an electron goes, destroys the interference pattern (for all observers).

but there's another experiment i got which i think could give real weirdness...\

"consider the same interference experiment,the interference pattern produced is used to illuminate the next source in series,which then produces a new interference pattern,this gets cascaded say 10 times and the final interference pattern is obtained on the wall.
now ,the observer, observing the final interference pattern is not known of the fact that there's another observer measuring the particle position in the first stage of interference,and viceversa

"will ur answer b the same(no interference pattern) or something else?
and if u think that the experiment is not possible,state the reason along
 
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  • #32


nouveau_riche said:
but there's another experiment i got which i think could give real weirdness...\

"consider the same interference experiment,the interference pattern produced is used to illuminate the next source in series,which then produces a new interference pattern,this gets cascaded say 10 times and the final interference pattern is obtained on the wall.
now ,the observer, observing the final interference pattern is not known of the fact that there's another observer measuring the particle position in the first stage of interference,and viceversa

"will ur answer b the same(no interference pattern) or something else?
and if u think that the experiment is not possible,state the reason along

This experiment can be done just fine, although you seem to be mixing electrons with photons.
But that's not really a problem, it doesn't really matter which of them you use.

Cascading through a number of interference patterns will reduce the chance that a photon/electron will reveal which slit an electron/photon goes through.
I believe that the result will be a mixture of an interference pattern and a destroyed interference pattern (for all observers).
 
  • #33


I like Serena said:
This experiment can be done just fine, although you seem to be mixing electrons with photons.
But that's not really a problem, it doesn't really matter which of them you use.

Cascading through a number of interference patterns will reduce the chance that a photon/electron will reveal which slit an electron/photon goes through.
I believe that the result will be a mixture of an interference pattern and a destroyed interference pattern (for all observers).
i think the result will still b the same as it was with previous experiment
 

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