How Is Power Related to Aerodynamic Drag in Cycling?

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SUMMARY

The discussion centers on the relationship between power output and aerodynamic drag in cycling, specifically referencing Lance Armstrong's performance during time trials. Armstrong maintains an average power output of 500 watts at a speed of 54 km/hr, with most of this power combating aerodynamic drag. The force of aerodynamic drag is defined by the equation Fdrag = 1/2 * CD * Pair * A * v^2, where CD is the drag coefficient (0.90 for cyclists), Pair is the air density (1.29 kg/m³), A is the cross-sectional area, and v is the velocity. The analysis concludes that the power required to overcome aerodynamic drag is proportional to the cube of the velocity (v^3).

PREREQUISITES
  • Understanding of aerodynamic drag and its formula: Fdrag = 1/2 * CD * Pair * A * v^2
  • Knowledge of power calculations in physics: Power = Force * Distance / Time
  • Familiarity with the concept of drag coefficient (CD) and its significance in cycling
  • Basic understanding of cross-sectional area and its impact on aerodynamics
NEXT STEPS
  • Research the effects of different drag coefficients (CD) on cycling performance
  • Explore methods to calculate cross-sectional area (A) for various cycling positions
  • Investigate the impact of speed on aerodynamic drag and power requirements
  • Learn about the role of rolling resistance and drivetrain efficiency in cycling power output
USEFUL FOR

Cyclists, sports scientists, and coaches interested in optimizing cycling performance through a better understanding of the physics of aerodynamic drag and power output.

shimizua
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Homework Statement


It is said that Lance Armstrong can maintain a average power output of 500 watts for a time trial. The additional power (above that needed to fight gravity) is primarily used to fight aerodynamic drag. On a flat time trial Lance is able to maintain an average speed of about 54 km/hr. Almost all of the power he generates on a flat time trial is used to fight aerodynamic drag. The force of aerodynamic drag is given by
Fdrag=1/2CDPairAv^2 (if any of that is confusing i posted the link to the pic
http://www.colorado.edu/physics/phys2010/phys2010_fa08/homework/LAlpedHuez/figures/fdrag.gif

The parameter CD is the coefficient of drag. It depends on the shape of the object moving through the air. A value of CD=0.90 is a reasonable estimate for a person on a bike. The parameter A is the cross-sectional area facing the airstream. It depends on how the rider is positioned on the bike. The parameter rair = 1.29 kg/m3 is the mass density of air, and v is the speed through the air. First show that the power needed to fight aerodynamic drag is proportional to v3. Estimate a value for Lance's cross-sectional area A during a flat time trial. Other losses (rolling friction, drive train friction, etc. are relatively small effects.)
so i am just unsure of why they are wanting to know anything about v^3.
some stuff that was given to us before this problem is this.
In 2004, for the first time ever the Tour de France bicycle race organizers set a time trial on the famous climb from Bourg-D'Oisans to the top of L'Alpe d'Huez. The stage was won by Lance Armstrong with a winning time of 39 minutes and 42 seconds. The time trial consisted of 1.5 km of relatively flat road followed by 14.0 km of climbing. The Tour organizers classify the difficulty of climbs using Categories 1 (hardest) through 5 (easiest). The L'Alpe d'Huez climb is rated 'H.C' (Haute Categorie or beyond category) due to its length and steepness. The bottom of the mountain, the 'Pied de cote', is at 740 m above sea level and the top is 1850 m above sea level. Lance covered the first 1.5 km in just over two minutes (2:05).
that should help some i think

Homework Equations


well i am pretty sure that power can by found by using Fd/t and since d/t = v. so just cube everything?

The Attempt at a Solution


well i am not really sure where to start. i know that for finding A we would just plug everything into the given equation. What i also don't know is if you go to the link and look then it looks like part of the equation says P(air) and we are given r(air), so i don't know if that is a typo or if we need to do something else also.
 
Last edited by a moderator:
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shimizua said:

Homework Statement


It is said that Lance Armstrong can maintain a average power output of 500 watts for a time trial. The additional power (above that needed to fight gravity) is primarily used to fight aerodynamic drag. On a flat time trial Lance is able to maintain an average speed of about 54 km/hr. Almost all of the power he generates on a flat time trial is used to fight aerodynamic drag. The force of aerodynamic drag is given by
Fdrag=1/2CDPairAv^2 (if any of that is confusing i posted the link to the pic
http://www.colorado.edu/physics/phys2010/phys2010_fa08/homework/LAlpedHuez/figures/fdrag.gif

The parameter CD is the coefficient of drag. It depends on the shape of the object moving through the air. A value of CD=0.90 is a reasonable estimate for a person on a bike. The parameter A is the cross-sectional area facing the airstream. It depends on how the rider is positioned on the bike. The parameter rair = 1.29 kg/m3 is the mass density of air, and v is the speed through the air. First show that the power needed to fight aerodynamic drag is proportional to v3. Estimate a value for Lance's cross-sectional area A during a flat time trial. Other losses (rolling friction, drive train friction, etc. are relatively small effects.)

Fdrag = 1/2*CD*Pair*A*v2

But what is power? Force * distance / time? And Distance / time is ...?

As for the rest just calculate it based on his estimated 500 watts right?
 
Last edited by a moderator:


yeah thanks for the help man.
 

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