1. The problem statement, all variables and given/known data Studetns examine the aerodynamics of a model car which has a drag force in air of 10 N at 10 m/s. They wish to estimate what the drag will be for a full scale model, and the energy lost on a given trip. The drag coefficient C remains constant C= 0.6. The cross-sectional area A of the car is increased to 2 times its original area, and the speed is now increased to 20 m/s. How much work does this car do in overcoming air resistance in a journey of 1000 m. Answer in joule. 2. Relevant equations new drag force = (C/0.5) * (area/original area)* original drag force then Energy to overcome drag = Work = force x distance. 3. The attempt at a solution (.6*.5)(20/10)(10)=24 24*1000=2400 but answer is 40000
Drag force is proportional to the cross-sectional area and velocity of the object. Since the drag coefficient remains the same, we can effectively ignore it. Thus it is clear that when I double cross-sectional area or velocity, the magnitude of the drag force would be doubled as well. When both are doubled simultaneously, the drag force is quadrupled to 40N. The relation between old and new drag force would be: [tex]\frac{F_{1}}{F_{2}} = \frac{A_{1} v_{1}}{A_{2} v_{2}}[/tex] The drag coefficient cancels out, so there is no need to include it. And, 24*1000=2400?? Do take more effort in putting forth your attempt here...