Rodrigues' formula can be derived using Legendre polynomials, which are defined by the equation n(x)=(x^2-1)^n. The derivation involves differentiating this equation, leading to a first-order differential equation: (1-x^2)f'n + 2nxfn = 0. Clarification was requested regarding the differentiation process used in the derivation. Further questions about the derivation are welcomed for additional explanation.
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#3
danny12345
22
0
n(x)=(x2-1)n. (20)
By differentiation we see that it satisfies the following first order differential equation,
(1-x2)f'n+2nxfn=0.
how did you get itb pleasez explain me the differentiation part