How is Stefan-Boltzmann's Law Derived from Statistical Mechanics?

  • Thread starter Thread starter Nikitin
  • Start date Start date
  • Tags Tags
    deriving Law
Click For Summary
SUMMARY

The discussion focuses on the derivation of Stefan-Boltzmann's Law from statistical mechanics, specifically within the context of black body radiation. The energy density of electromagnetic (EM) radiation inside a cavity at temperature T is proportional to T^4, represented mathematically as u(T). The relationship between the total EM energy U, volume V, and the density of states is clarified, emphasizing that the number of photons N and their mean energy are crucial in understanding the derivation. The discussion also highlights the quantization of photon wavelengths in a cavity, leading to discrete energy states.

PREREQUISITES
  • Understanding of black body radiation and its properties.
  • Familiarity with statistical mechanics concepts, particularly energy density and density of states.
  • Knowledge of quantum mechanics, specifically the quantization of energy levels.
  • Basic grasp of thermodynamics, especially the relationship between temperature and energy.
NEXT STEPS
  • Study the derivation of Planck's Law to understand the quantization of electromagnetic radiation.
  • Explore the concept of density of states in quantum mechanics and its implications for particle physics.
  • Learn about the relationship between temperature and energy in thermodynamic systems.
  • Investigate the implications of black body radiation in real-world applications, such as astrophysics and thermal imaging.
USEFUL FOR

Students of physics, particularly those studying thermodynamics and statistical mechanics, as well as researchers interested in the foundational principles of black body radiation and quantum mechanics.

Nikitin
Messages
734
Reaction score
27
Hi! As my professor is a bit crazy (in a good way), he derived Stefan-Boltzmann's law in my intro thermodynamics class. However, since he introduced loads of concepts from statistical mechanics and such I got a bit confused on some points. Anyway:

The first part of the derivation:

Inside a black body at temperature ##T## you have a cavity, of which inside the energy-density of the EM radiation is ##u## and is proportional to ## T^4##.

Then: ##u(T) = \int d u = \int_0^{\infty} df \cdot \frac{du}{df}##. From there ##\frac{du}{df}= \frac{d(U/V)}{df} = \frac{d( N <E>/V)}{df} =\frac{<E>}{V} \cdot \frac{dN}{df}##, where ##<E>## is the mean energy per state ("swinging mode") and ##dN/df## is the density of states.

My question: Ehm, what happened here? ##df## is a frequency band, ##U## is the total EM energy inside the cavity and ##V## its Volume. Then shouldn't ##N## be the number of photons, and ##<E>## be the mean energy of the photons? Can somebody explain to me how he linked that to "swinging modes" and "density of states" ??

Later he starts talking about frequency space, and density of states and so on. This confuses me. I should probably ask him personally about that once I've got the stuff above cleared up.
 
Last edited:
Physics news on Phys.org
Don't know if you had it explained to you already, but here's what I dusted off from very old memories of this:
Point is that photon wavelengths quantummechanically no longer have a continuous spectrum, but have to "fit" in the cavity. Consequence is that the possible ##\vec k## are grid points in 3D k space. Energy is proportional to k2, so the number of allowed photons with an energy between E and E + dE is proportional to the number of grid points in a shell between radius k and k+dk.

The step you "Ehm" about the most would be ##{d(U/V)\over df}={ d(N<E>/V)\over df}## ? This just says that total EM energy ##U## in a frequency band f to f+df is the number of photons that can have this energy times the energy per photon. Classically this number is infinite, QM says it's limited to this number of grid points between E and E + dE.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
4
Views
1K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
4
Views
5K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K