How Is the Function f(x) Defined Between Disjoint Sets A and B Continuous?

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SUMMARY

The function f(x) defined as f(𝑥) = d(𝑥, B) / (d(𝑥, A) + d(𝑥, B) is continuous for points in Rⁿ where A and B are closed disjoint sets. The distance function d(𝑥, A) is continuous for any set A, and since the sum of continuous functions is continuous, f(x) inherits this property. The closedness and disjointness of sets A and B ensure that the denominator is non-zero, confirming the function's definition across its domain.

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  • Understanding of distance functions in metric spaces
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  • Familiarity with closed and disjoint sets in Rⁿ
  • Proficiency in limit theorems, particularly Cauchy's test
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Homework Statement


\underline{x} point in R^{n} A \subset R^{n}
the distanse between \underline{x} to A is definde as d(\underline{x},A) = \left\{ inf{||\underline{x} = \underline{a}|| | a \in A \right\}

A,B are closed Disjoint sets in R^{n} we define f(\underline{x}) = \frac{d(\underline{x},B)}{d(\underline{x},A) + d(\underline{x},B)}


to each \underline{x} \subset R^{n} and \underline{y} \subset R^{n} <br /> <br /> |d(\underline{x},A)-d(\underline{y},A)| \leq||\underline{x}-\underline{y}||

Prove that f(\underline{x}) Continuous

Homework Equations


everything in calculus


The Attempt at a Solution



Well I've tried with Cauchy test for limits of function but this does not give me a Continuous function..
from there I am A bit stuck.
Thank you.
 
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Show the function g(x) = d(x,E) is continuous for any set E, then the sum of such functions must be continuous, and the quotient as well, where it is defined. And use the disjointness and closedness to show your function is defined everywhere (the denominator is non-zero).
 
Thank you
I know that I need to prove that g(x) = d(x,E) in any set.
This is why I said I tried with Cauchy test for limits, But I did not managed to do it.
Any idea of who to prove this?
Thank you.
 
The last part about x and y is a pretty big hint for how to prove continuity
 

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