How is Translation Equilibrium Achieved in a Torque Experiment?

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SUMMARY

The discussion centers on achieving translation equilibrium in a torque experiment involving a balanced meter stick. Participants calculated torque values by attaching masses at various points on the stick. The key conclusion is that translation equilibrium, defined by Fnet = 0, is satisfied through the establishment of rotational equilibrium, where the net force acting on the system is zero due to the distribution of forces at varying distances from the pivot point.

PREREQUISITES
  • Understanding of torque and its calculation.
  • Knowledge of rotational equilibrium principles.
  • Familiarity with the concept of net force in physics.
  • Basic grasp of mass and gravitational acceleration (Mass * Acc Due To Gravity).
NEXT STEPS
  • Study the principles of torque calculation in detail.
  • Explore the concept of rotational equilibrium further.
  • Learn about the relationship between force, mass, and acceleration.
  • Investigate practical applications of translation and rotational equilibrium in real-world systems.
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Students in physics courses, educators teaching mechanics, and anyone interested in understanding the principles of torque and equilibrium in physical systems.

chrisfnet
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Homework Statement



We recently did a lab where we calculated various torque values for various systems. Basically, we attached mass by a hanger at different areas on a balanced/pivoted meter stick.

At the end of the lab, he asks the question "How is the condition for translation equilibrium Fnet = 0 satisfied in this experiment?

I think I understand why, but I can't really explain it in a comprehensible manner.

The Attempt at a Solution



I believe it is because we're establishing rotational equilibrium and at equilibrium any net force acting on the system is 0 (by definition). But.. how do I explain this? The forces are all different (considering Mass * Acc Due To Gravity), but they even out because they're placed at different distances from the pivot point to put the system into rotational equilibrium.
 
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