How Is Trigonometry Used to Calculate Flagpole Heights?

  • Context: MHB 
  • Thread starter Thread starter ai93
  • Start date Start date
  • Tags Tags
    Angle
Click For Summary

Discussion Overview

The discussion revolves around calculating the height of a flagpole using trigonometric principles, specifically through the application of angles of elevation from a fixed horizontal distance. The context includes both diagrammatic representation and mathematical reasoning related to the problem.

Discussion Character

  • Mathematical reasoning
  • Technical explanation
  • Homework-related

Main Points Raised

  • One participant presents the problem setup, including angles of elevation and horizontal distance, and attempts to draw a diagram.
  • Another participant suggests using tangent functions to express the relationships between the height of the flagpole and the angles of elevation, proposing to eliminate one variable using another equation.
  • A different participant reiterates the tangent relationships and provides a calculation for the height of the flagpole, arriving at a value of approximately 13.33 meters.
  • Another participant reformulates the equations to express the height in terms of the tangent of the angles, confirming the height calculation while emphasizing the importance of avoiding intermediary rounding to maintain accuracy.
  • There is a discussion about the relative sizes of the angles of elevation, with a participant noting that the angle corresponding to the higher point must be greater.

Areas of Agreement / Disagreement

Participants generally agree on the approach to solving the problem using trigonometric functions, and some calculations align closely. However, there is no explicit consensus on the method of rounding or the best practices for accuracy in calculations.

Contextual Notes

Some participants express uncertainty about the accuracy of their calculations and the implications of rounding during the problem-solving process. There are also assumptions regarding the relationships between the angles and the heights that are not fully explored.

Who May Find This Useful

Students or individuals interested in applying trigonometry to real-world problems, particularly in geometry and physics contexts, may find this discussion beneficial.

ai93
Messages
54
Reaction score
0
A vertical flagpole is fixed at the top of a vertical wall. From a point which is 120m measured horizontally from the base of the wall the angle of elevation to the top of the flagpole is 30 degrees, and the angle of elevation to the bottom of the flagpole is 25 degrees.

a) Draw a clearly labelled diagram to represent this situation

b) Calculate the length of the flagpole correct to 2 dp

View attachment 3811

I have attempted to draw the diagram, and hopefully figured the height out. Although I could be completely wrong!
 

Attachments

  • photo (4).JPG
    photo (4).JPG
    21.4 KB · Views: 138
Mathematics news on Phys.org
I would draw the diagram as follows:

View attachment 3812

From this, we see:

$$\tan\left(25^{\circ}\right)=\frac{w}{120}\tag{1}$$

$$\tan\left(30^{\circ}\right)=\frac{w+h}{120}\tag{2}$$

Now, can you use (1) to eliminate $w$ in (2)?
 

Attachments

  • wallandflag.png
    wallandflag.png
    1.7 KB · Views: 123
MarkFL said:
I would draw the diagram as follows:

View attachment 3812

From this, we see:

$$\tan\left(25^{\circ}\right)=\frac{w}{120}\tag{1}$$

$$\tan\left(30^{\circ}\right)=\frac{w+h}{120}\tag{2}$$

Now, can you use (1) to eliminate $w$ in (2)?

$$\tan\left(25^{\circ}\right)=\frac{w}{120}\tag{1}$$

$$w=tan(25)x120=55.95$$

$$tan(30)=\frac{55.95+h}{120}$$

$$\therefore tan(30) \cdot 120 = 55.95+h$$

$$69.28+55.95+h$$

$$69.28-55.95=h$$

$$\therefore h=13.33$$

I think that's right

- - - Updated - - -

If I am given a similar question with two angles. The biggest angle would obviously be the outer angle?
 
I would rewrite (2) as:

$$\tan\left(30^{\circ}\right)=\frac{w}{120}+\frac{h}{120}$$

Then use (1) to obtain:

$$\tan\left(30^{\circ}\right)=\tan\left(25^{\circ}\right)+\frac{h}{120}$$

And then solving for $h$, we get (in meters):

$$h=120\left(\tan\left(30^{\circ}\right)-\tan\left(25^{\circ}\right)\right)\approx13.33$$

Your answer is correct, however, it is best to obtain the exact value first, and then only at the very end do your rounding. Sometimes intermediary rounding can cause your end result to be inaccurate.

Regarding which angle is larger, we know that if two rays have the same terminus, but one passes through a higher point over the same horizontal distance, then its angle of elevation must be greater. :D
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 5 ·
Replies
5
Views
6K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K