How Is Work Calculated for a Moving Crate?

[joe465]

Homework Statement

Calculate the work done on the crate during the journey

Homework Equations

WD=F*S

The Attempt at a Solution

I know its simple but I am just double checking more than anything, the force pulling the crate is 482.96N and the distance is 20M.

Now i would presume 482.96*20= 9659.2J

My book however says that the force is the force we are opposing against so what force would this be?

Thanks, Joe

 

[Doc Al]

Can you please post the full problem exactly as given.

 

[joe465]

The first of these concerns the transport of crates
across the floor of a factory. This is accomplished by using a drag line connected
to an electric motor. Crates are hooked on to the line and dragged from one
location within the factory to another across a series of rollers.

the original problem was at :https://www.physicsforums.com/showthread.php?t=521477
On there also has an image of what i mean since it won't let me upload it twice.

I have currently calculated:

horrizontal component acting on the crate
the acceleration experienced by the crate
the speed of the crate at the end of a 20m journey
the kinetic energy of the crate at the end of the journey
the duration of the journey

It now wants the Work done on the crate during the journey

If that's any better, Cheers

 

[Doc Al]

It now wants the Work done on the crate during the journey

You've calculated it correctly.

 

[joe465]

Thankyou very much for your time and help