Work calculation for lifting a Tetrahedron-shaped object from the water

[Charles Link]

It’s a work integral of a fully submerged volume. This is an incomplete thread because the discussion moved to a private conversation. I believe the OP is satisfied.

The OP looks to me to still be doing an incorrect computation of the buoyant force.

 

[Frabjous]

The OP looks to me to still be doing an incorrect computation of the buoyant force.

He’s calculating the work done by gravity and buoyancy of a fully submerged constant volume that is lifted height L-h.

 

[Charles Link]

He’s calculating the work done by gravity and buoyancy of a fully submerged constant volume that is lifted height L-h.

Thank you=I just re-read the title of the post=the work to lift the object. I would expect to see $W=\int F \cdot ds$, but my mistake. :)