wallace13
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An irregularly shaped chunk of concrete has a hollow spherical cavity inside. The mass of the chunk is 34 kg, and the volume enclosed by the outside surface of the chunk is 0.035 m3. What is the radius of the spherical cavity?
D=m/v
4/3 pi r^3= volume of a sphere
2200 kg/ m cubed (density of concrete)= 34 kg/ v
V= .01545
.035-.01545= .01955
.01955= 4/3pi r^3
r=.167 m
D=m/v
4/3 pi r^3= volume of a sphere
2200 kg/ m cubed (density of concrete)= 34 kg/ v
V= .01545
.035-.01545= .01955
.01955= 4/3pi r^3
r=.167 m