What is the radius of the spherical cavity?

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SUMMARY

The discussion centers on calculating the radius of a hollow spherical cavity within a concrete chunk weighing 38 kg and having a total volume of 0.025 m³. To determine the radius, one must utilize the density of concrete, which is approximately 2400 kg/m³. By calculating the mass of a solid concrete sphere with the same volume, the radius can be derived using the formula for the volume of a sphere, V = (4/3)πr³. This approach eliminates the need for surface area calculations.

PREREQUISITES
  • Understanding of basic geometry, specifically the volume formula for spheres.
  • Knowledge of concrete density, specifically the density of concrete at approximately 2400 kg/m³.
  • Familiarity with mass and volume relationships in physics.
  • Ability to perform algebraic manipulations to solve for unknown variables.
NEXT STEPS
  • Research the density of various materials, focusing on construction materials like concrete.
  • Learn how to calculate the volume of a sphere using the formula V = (4/3)πr³.
  • Explore the relationship between mass, volume, and density in physics.
  • Investigate practical applications of hollow structures in engineering and architecture.
USEFUL FOR

Students in physics or engineering, construction professionals, and anyone interested in material properties and structural calculations.

ramalik
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An irregularly shaped chunk of concrete has a hollow spherical cavity inside. The mass of the chunk is 38 kg, and the volume enclosed by the outside surface of the chunk is 0.025 m3. What is the radius of the spherical cavity?

I think you have to find the surface area to solve for the radius and all this has to do with the density of the sphere, but I don't know how to connect it all
 
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No need to mess around with surface areas, but you do need to use the density of concrete. (Look it up!) Hint: If the chunk were solid concrete, what would be its mass?
 

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