How long after the decay do ##e^{-}## and ##e^{+}## Collide

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SUMMARY

The discussion centers on the collision time of an electron (##e^{-}##) and a positron (##e^{+}##) produced from the decay of a fundamental particle in a magnetic field of 3.53 mT. The period of motion for these particles is given by the formula ##T=\frac{2\pi m_{e}}{qB}##. The key conclusion is that the particles collide at time ##t=T/2## when they move in opposite directions, contrary to the initial assumption that they would collide after one full rotation at time ##t=T##.

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Homework Statement


A particular type of fundamental particle decays by transforming into an electron ##e^{-}## and a positron ##e^{+}##. Suppose the decaying particle is at rest in a uniform magnetic field of magnitude 3.53 mT and the ##e^{-}## and ##e^{+}## move away from the decay point in paths lying in a plane perpendicular to the magnetic field. How long after the decay do the ##e^{-}## and ##e^{+}## collide?

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The Attempt at a Solution



The period which is all we need to solve this problem can be found to be ##T=\frac{2\pi m_{e}}{qB}## for this problem. Personally I think these particles would collide at ##t=T## but in the solutions manual it says they collide at ##t=T/2##. This doesn't entirely make sense to me since although both the particles are moving at a speed ##v## they won't have completed the entire rotation at ##T/2## although they will have traveled a total distance ##2\pi r##
 
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Maybe I'm missing something, but won't they collide after each has gone half way around the circle?
 
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haruspex said:
Maybe I'm missing something, but won't they collide after each has gone half way around the circle?
I understand the path they take now. I assumed that both electrons were traveling in the same direction at the start, in this case it will be T before they collide. But if the angle between the two speeds is 180 then it only takes T/2.
 

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