A particle A (mother particle) with a mass of mA decays to two particles B and C (daughter
particles) with mass values of respectively mB and mC. Calculate momentum of the two
daughter particles, pB and pC. (at first the mother particle is at rest)
The Attempt at a Solution
I would do conservation of momentum which would give me that pB=-pC since pA is 0 if it is at rest. then to do conservation of energy, before the decay E=mAc^2 and energy after the decary would be just replacing for the respective masses and momentums, and then solving for pB (or pC).
Where x is the momentum pB and a=mass of a, b=mass of b, m=mass of c and then c is the speed of light constant
Is this okay ? I am a bit unsure if I am missing something because of special relativity.