How Long and Fast Does a Diesel Train Accelerate to Cover 6km?

  • Thread starter Thread starter scotthands
  • Start date Start date
  • Tags Tags
    Kinematics Train
Click For Summary

Homework Help Overview

The problem involves a diesel train that accelerates uniformly from rest to a speed of 60 km/h over a period of 6 minutes, with the goal of determining the total time taken to cover a distance of 6 km and the acceleration during the initial phase of travel.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to incorporate acceleration into their calculations but expresses uncertainty about how to determine the acceleration value. Some participants clarify the time taken for acceleration and suggest methods for calculating distance and time.

Discussion Status

The discussion includes attempts to derive acceleration and distance traveled during the acceleration phase. Some participants provide calculations and reasoning regarding the distance covered and the remaining distance at constant speed, indicating a progression in the discussion. However, there is no explicit consensus on the final outcome of the calculations.

Contextual Notes

Participants are working within the constraints of the problem statement, which specifies the acceleration time and final speed but does not provide additional context or constraints regarding the overall journey.

scotthands
Messages
25
Reaction score
0

Homework Statement



A deisel train accelerates uniformly from rest to reach 60km/hr in 6 minutes, after which the speed remains constant.
Calculate the total time taken to travel 6km and the acceleration.

Homework Equations


s= ut
v= u+at
s=ut + 0.5*at^2

The Attempt at a Solution


I'm not sure how to incorporate the accelaration part into the question.
I tried t=(v-u)/a but idon't know what to put in for the acceleration.
 
Last edited:
Physics news on Phys.org
That is not a question.
 
yeah i accidentally entered the post before i finished it, it's finished now.
 
Well the time taken to accelerate is 6min, because we are given that.

First find the distance traveled in the 6mins it is accelerating.

6mins = 1/10 hours. We must find the acceleration.

Re-arrange v= u+at for acceleration:

a = (v - u)/t = 60/(1/10) = 600 km/h^2

Now find the distance it travels:

s=ut + 0.5*at^2 = 0 + 0.5*600*(1/10)^2 = 3km

Therefore the train still has 3km left to go, but now it is traveling at a constant 60km/h, so the time taken is:

s = ut
so:
t = s/u = 3/60 = 1/20 of an hour = 3mins

So the total time for the journey is 9mins
 
thank you
 
My Pleasure.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 5 ·
Replies
5
Views
8K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
7K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
3
Views
4K
  • · Replies 24 ·
Replies
24
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
2K